p^2+1.75p-0.5=0

Solution for p^2+1.75p-0.5=0 equation:

p^2+1.75p-0.5=0

a = 1; b = 1.75; c = -0.5;
Δ = b2-4ac
Δ = 1.752-4·1·(-0.5)
Δ = 5.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.75)-\sqrt{5.0625}}{2*1}=\frac{-1.75-\sqrt{5.0625}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.75)+\sqrt{5.0625}}{2*1}=\frac{-1.75+\sqrt{5.0625}}{2}
$